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Rod when updating my zen cart the manager popped up a warning that there was a ozpost module upgrade Version V2.0.9
I am looking to download it but can only seem to find version V2.0.8 please could you point me to the very latest update as this module is so good and works well for me.
Thank
Steve
I've no idea why the site admins are taking so long with releasing this update, but the latest version can always be downloaded from ozpost.netQuote:
Originally Posted by Bexley
Cheers
Rod
Dear Rod
I am testing out the ozpost and I tried to checkout an item 36 x 13 x 17 cm , the 3kg regular satchel option still appears however in fact this item can't fit entirely inside 3kg regular satchel. I need to adjust by changing one side 13cm to 14cm.
I am wondering how does ozpost calculate whether item fit or not fit in satchel? what volume does ozpost use for 500g and 3kg satchel?
Thanks.
Good question. I don't think anyone has asked before.Quote:
Originally Posted by zekin
It was a tough call on how to make this determination, and I ended up using the length and girth measurements. I then used a number of objects to pack the bags out to various shapes (eg, teatowels, books), taking note of how much of the length was being lost due to distortion and then adjusted numbers down to suit.
Example: The 3gk bag measures 40x30 'flat' - This gives a (theortical) max length of 40 and girth of 60 (think of a single sheet of paper)
Packed out with teatowels to produce a tubular shape (like a rolled up sleeping bag) distorts the ends so the max length that will actually fit is about 37cm, so this is what the module uses (along with weight).
Don't know, I haven't factored that in. Also, be aware that the Fastway satchels are a different size to the Australia post ones. I am assuming you are referring to the AustraliaPost ones?Quote:
Originally Posted by zekin
Cheers
Rod
Hi Rod, yes I meant AUpost's satchel.
Satchel is useful IF the customer is so far away from you. eg WA vs QLD. However if the software judges the items can fit in satchel but in fact it can't, there will be a little problem because need to communicate with customer for postage correction etc.
When you say about max length of 40 and girth of 60, I do have some thought and I like to share with you.
A 30x40 satchel's max length is 40 when you are sending a sheet of paper. in reality the box is 3D, so the 40 x 30 satchel should be able to fit a box with (sum of its length and width) x 2 equals to 80, and (the sum of last side and width) x 2 equals to 60.
So having this sort of algorithm, maybe we could validate if the items can be fit in the satchel.
I have thought about using volume to validate but i realise there will be a problem. Since (W+L)x2 = 80 and (W+H)x2 = 60, so we can work out what the W, L and H be and then work out the possible volumes. But... now i did some mathematics.
If a box has 20 x 20 x 10 (this can fit the satchel by checking with above formula), it has 4000cc.
if a box has 15 x 25 x 15 (this fits too), but it has 5625cc
So my conclusion is that maybe we can just validate the L , W and H and forget about volume.
FYI In case anyone has a problem fitting items in the 5kg bag.
My Australia Post office tells me that with the 5kg Express satchels, you are allowed to leave the perferated confirmation slip on the bag if required to fit something in the bag. I only asked this as I have one product that will not fit by about 3cm in length. The only problem with this being you will need to right down the details which normally goes on this slip and get it stamped for tracking.
Cheers
Sure... :no:Quote:
Originally Posted by zekin
Yes, so is a sheet of paper (3D)... and 2 sheets, 5, 10, and 500 sheets.Quote:
Originally Posted by zekin
The 'problem' is that we need to fit a 3d object into an object with only 2 known dimensions.
Errr, why are we doubling the sum of the length by width? I don't quite follow.Quote:
Originally Posted by zekin
Girth = L x (2W + 2H)
The largest item that will fit (theoretically) is Length 40cm x Girth 60cm
Consider the volume as being forgotten already. :smile:Quote:
Originally Posted by zekin
The current code already does what you are suggesting, namely, comparing the length (which has a known limit of 40cm max). and the width/height of the actual parcel (by calculating the girth) and comparing it with the max girth that will fit into the satchel.
It isn't possible to use the absolute values for width or height, because the satchel itself is variable in that it can range anwhere between ~0 x30cm to 30x~0, with a mid value being 15x15.
Using this method, your parcel measuring 36 x 13 x 17 cm should *just* fit. Clearly this isn't the case, so which dimension do I need to adjust in order to force a pass/fail ?
You previously stated "I need to adjust by changing one side 13cm to 14cm".
Just to clarify, you need to do this to make the Satchel to *not* appear as an option? - Which means the server needs to test against lower values to force a 'fail' status.
This is entirely possible; for 2 reasons. 1. The 'worst possible length' check wasn't necesarily taken under the worst possible condition, and 2, I haven't made any allowance for 'tightness of fit' of the girth. I am quite happy to adjust any/either of these (downwards) in order to avoid false positives. All I need know is by how much and in what dimension.
Using your numbers as an example, in order to make it work for you the server will need to fail the 'isSatchel' if it tested against a girth of 59cm rather than the current 60cm?
If I do that, will the length also be an issue?
<30 seconds later>
OK, I've tweaked the girth check .. Please lemme know if your parcel succesfully fails now.
Cheers
Rod
ps. One of the aims of the ozpost module is to 'protect the merchant', so on this basis I'd rather have the module NOT show an option where it could rather than show it when it shouldn't. (is that double speak or what?)
Thanks for the advice, but this tells me that I need to tweak the pass/fail figures a little in order to avoid this situation. As of now the check for valid length has been reduced by 4cm (from 50 to 46). Like the satchels themselves, this isn't set in concrete and may be subject to further tweaking if and when advised.Quote:
Originally Posted by rick99
Cheers
Rod
Because a satchel when it is flat it's 40cm long right? , but it actually have two sides, front and back, so, imagine this 40cm of front and back form a 3d shape, then this 3d shape must have 80cm , theoretically 2 x one side and 2 x adjacent side (a rectangle has 4 sides) formed by the back of satchel (40cm) and the front of satchel (another 40cm).Quote:
Originally Posted by RodG
hmm headache. :blink:
Am I on right track?
Hi, just to report you, yes it fails now.Quote:
Originally Posted by RodG