Hello everyone,

I'm trying to achieve the following at the moment:



As you can see the top checkout box is what it looks like currently but I'd like to show the product quantity instead of the maximum that can be ordered. I have found the file which I believe is:

tpl_document_product_info_display.php

and I believe this is the correct section that I'll need to edit:

PHP Code:
<!--bof Add to Cart Box -->
<?php
if (CUSTOMERS_APPROVAL == and TEXT_LOGIN_FOR_PRICE_BUTTON_REPLACE_SHOWROOM == '') {
  
// do nothing
} else {
?>
            <?php
    $display_qty 
= (($flag_show_product_info_in_cart_qty == and $_SESSION['cart']->in_cart($_GET['products_id'])) ? '<p>' PRODUCTS_ORDER_QTY_TEXT_IN_CART $_SESSION['cart']->get_quantity($_GET['products_id']) . '</p>' '');
            if (
$products_qty_box_status == or $products_quantity_order_max== 1) {
              
// hide the quantity box and default to 1
              
$the_button '<input type="hidden" name="cart_quantity" value="1" />' zen_draw_hidden_field('products_id', (int)$_GET['products_id']) . zen_image_submit(BUTTON_IMAGE_IN_CARTBUTTON_IN_CART_ALT);
            } else {
              
// show the quantity box
              
$the_button PRODUCTS_ORDER_QTY_TEXT '<input type="text" name="cart_quantity" value="' . (zen_get_buy_now_qty($_GET['products_id'])) . '" maxlength="6" size="4" /><br />' zen_get_products_quantity_min_units_display((int)$_GET['products_id']) . '<br />' zen_draw_hidden_field('products_id', (int)$_GET['products_id']) . zen_image_submit(BUTTON_IMAGE_IN_CARTBUTTON_IN_CART_ALT);
            }
    
$display_button zen_get_buy_now_button($_GET['products_id'], $the_button);
  
?>
  <?php if ($display_qty != '' or $display_button != '') { ?>
    <div id="cartAdd">
    <?php
      
echo $display_qty;
      echo 
$display_button;
            
?>
          </div>
  <?php // display qty and button ?>
<?php 
// CUSTOMERS_APPROVAL == 3 ?>
<!--eof Add to Cart Box-->
I know my way around HTML/CSS but haven't started to learn PHP yet. If someone can assist me with this in any way I will be truly grateful!

Thanks,
Jack