using jquery ajax POST method returning 500 error

[warroyo90]

hi i am trying to use this code but keep receiving a 500 internal server error when this runs. is this an issue in my script or do i need to use it differently for zen cart?

jQuery.ajax({
   type: "POST",
   url: "/includes/templates/theme376/phpScripts/check.php",
   data: 'partNum='+ partNum,
   cache: false,
   success: function(response){
if(response == 1){
	$('#partNum').css('border', '3px #C33 solid');	
	$('#tick').hide();
	$('#cross').fadeIn();
	}else{
	$('#partNum').css('border', '3px #090 solid');
	$('#cross').hide();
	$('#tick').fadeIn();
	     }

}
});

[DrByte]

Zen Cart is set up to prohibit access to any ".php" files located anywhere inside/under the /includes/ folder.
You will need to put your script someplace else. It cannot sit in /includes/templates/ nor anywhere else under /includes/

[warroyo90]

Zen Cart is set up to prohibit access to any ".php" files located anywhere inside/under the /includes/ folder.
You will need to put your script someplace else. It cannot sit in /includes/templates/ nor anywhere else under /includes/

I also tried putting it in the root directory and it still returned the error. I tried including a php file that connects to the db without using the global $db object but when I run a query for example

$query = "SELECT products_model FROM products WHERE products_model = '$partNum' LIMIT 1";

$result = mysql_query($query);
$row = mysql_fetch_assoc($result);
print_r($row); 

I do not recieve a 500 error but the query returns no results. so with this said how can I make an ajax call to a php file that runs a query in zen cart ?

[RodG]

how can I make an ajax call to a php file that runs a query in zen cart ?

The question is, why would you want to? Couldn't you use just plain javascript and/or PHP?

Cheers
Rod

[warroyo90]

The question is, why would you want to? Couldn't you use just plain javascript and/or PHP?

Cheers
Rod

well the reason I would want to is becuase I would liek to query the server on a keyup function and display the results in a div and also check to make sure the model # entered is in the db without doing page refresh ...if you think this could be accomplished more simply by javascript and php please give a in detail description I would love to know. I also have got it figured out and it is working great.

[RodG]

well the reason I would want to is becuase I would liek to query the server on a keyup function and display the results in a div and also check to make sure the model # entered is in the db without doing page refresh ..

You don't nedd AJAX for that, well not unless the site you are querying isn't the same site that you are making the query from.

.if you think this could be accomplished more simply by javascript and php please give a in detail description I would love to know.

The answer is contained in my line above.

I also have got it figured out and it is working great.

What did you do? Get rid of the AJAX call?

If not, I'm interested how you did solve the problem, because I do have a real need for this, in that the data I'm after is on a remote server who's permissions deny such access.

Cheers
Rod