Javascript Detection in user's browser

[ericpeng]

Hi,

Is there any way can detect if browser's Javascript is on?
I knwo the <noscript>,
but I would like to have code in
includes/modules/sidebox/YOUR_Template/newsidebox.php
like following

if ($javascript_on) {
require_once (DIR_WS_CLASSES .'newsidebox_generator.php');
....
$right_arrow = false;
$title_link = false;
require($template->get_template_dir($column_box_default, DIR_WS_TEMPLATE, $current_page_base,'common'.) . '/' . $column_box_default);
}

Thanks
Eric

[yellow1912]

You can have your javascript call a php file, this file will set the session $_SESSION['js_on'] = true; for example. Then in your php, check if $_SESSION['js_on'] is true.

[ericpeng]

You can have your javascript call a php file, this file will set the session $_SESSION['js_on'] = true; for example. Then in your php, check if $_SESSION['js_on'] is true.

Hi,

Sorry, I tried for 3 days, I don't even know where to start.
Would you give me a simple sample?

What I want to do is:
I got two sidebox(category boxes), if javascript==on call one of the box
else call the other one.

I did find a sample from the internet, but I don't know where it should be in zencart.
<?php
session_start();
if (!isset($_SESSION['js_on']) || $_SESSION['js_on'] == false)
{
if (isset($_POST['jstest'])) {
$_SESSION['js_on'] = true;
} else {
echo '<form name="jsform" id="form1" method="post" action="" style="display:none">';
echo '<input name="jstest" type="hidden" value="js_on" />';
echo '<script type="text/javascript" language="javascript">';
echo 'document.jsform.submit();';
echo '</script>';
echo '</form>';
$_SESSION['js_on'] = false;
}
}
// rest of script goes here....
// etc
echo "javascript is ".($_SESSION['js_on'] ? "on":"off")."<br>";
echo 'normal script here';
?>

Thanks
Eric

[swguy]

http://www.thatsoftwareguy.com/zenca...t_enabled.html

[ericpeng]

http://www.thatsoftwareguy.com/zenca...t_enabled.html

Thanks.
But I don't want to put the message on the screen.
I guess the session idea is good, but I don't know how to do it.

Eric

[yellow1912]

It's pretty simple, but not straight forward, I will give you some hints since I know how it can work but I dont have any testing code done:

You will need to use AJAX here, the idea is to call a php file onload using js, this php file will set the session, and in the main page you will check if this session is set or not.

This snippet here can give you some idea:
http://www.webtoolkit.info/ajax-file-upload.html

Please note that in this snippet the upload.php file in called when the form is submitted, in your case you will want to call the file when the page is loaded, so you will init it in body onload.

Now in your php file, assuming you put it in store root dir:
1. you have to include application top first to init session
require_once('includes/application_top.php');
2. The set the session
$_SESSION['js_on'] = true;

And that's it.

[yellow1912]

1 more thing: if you want to check the javascript setting EACH time the page is loaded, the remember to set $_SESSION['js_on'] = false; after you check it.

[yellow1912]

Okie, I did a test and find out it's a bit simpler that I thought, still have some small problems tho:

in your includes/templates/your_template/jscript
Create a new file called jscript_check.php with the following content:

<script type="text/javascript"
         src="jscript_check.php">
</script> 

Now in the store root folder (the folder that contains "includes" folder)
Create a new file called jscript_check.php with the following content:
<?php
require('includes/application_top.php');
$_SESSION['js_on'] = true;
?>


That's it. However, for some reason, the sessions is only set on the 2nd load of the page. So say if the customer lands on the site, and then visit another page or refresh the page --> the session is set.
It can be something to do with the require('includes/application_top.php'); since it executes lots of things and slows down the whole script.
One thing you can do is: you have to go in and see how zen session is init, and you have to only take the part that init the session.

I tried in the js file:

<script type="text/javascript"
         src="jscript_check.php?zenid=<?php echo zen_session_id(); ?>">
</script>

and then in the php file:

<?php
    session_name('zenid');
    if (isset($_GET['zenid'])) 
          session_id($_GET['zenid']);
      
      session_start();
    $_SESSION['js_on'] = true;
?>

The zenid is passed in correctly but the session is not. So yeah, let me know if you get it working.

Regards.

[ericpeng]

Okie, I did a test and find out it's a bit simpler that I thought, still have some small problems tho:

in your includes/templates/your_template/jscript
Create a new file called jscript_check.php with the following content:

<script type="text/javascript"
         src="jscript_check.php">
</script> 

Now in the store root folder (the folder that contains "includes" folder)
Create a new file called jscript_check.php with the following content:
<?php
require('includes/application_top.php');
$_SESSION['js_on'] = true;
?>


That's it. However, for some reason, the sessions is only set on the 2nd load of the page. So say if the customer lands on the site, and then visit another page or refresh the page --> the session is set.
It can be something to do with the require('includes/application_top.php'); since it executes lots of things and slows down the whole script.
One thing you can do is: you have to go in and see how zen session is init, and you have to only take the part that init the session.

I tried in the js file:

<script type="text/javascript"
         src="jscript_check.php?zenid=<?php echo zen_session_id(); ?>">
</script>

and then in the php file:

<?php
    session_name('zenid');
    if (isset($_GET['zenid'])) 
          session_id($_GET['zenid']);
      
      session_start();
    $_SESSION['js_on'] = true;
?>

The zenid is passed in correctly but the session is not. So yeah, let me know if you get it working.

Regards.

Hi,

Thank you so much for the code.
But I don't understand the "AJAX file upload" part, would you please give me some more information.

Thanks

[ericpeng]

Hi,

Thank you so much for the code.
But I don't understand the "AJAX file upload" part, would you please give me some more information.

Thanks

I guess my question is how can I init it in body onload ?

Thanks