The statement is testing conditions for some situation, based on $key which stands for the name of the current array-item key in the array being evaluated, and $value which holds the value of the current key.PHP Code:if ( (!in_array($key, $exclude_array)) && (strlen($value) > 0 || is_array($value) && array_filter($value) ) && ($key != 'main_page') && ($key != zen_session_name()) && ($key != 'error') && ($key != 'x') && ($key != 'y') ) {
Breaking down the statement,
if ( (!in_array($key, $exclude_array))
---> the key is not in a list of keys to exclude,
&& (strlen($value) > 0 || is_array($value) && array_filter($value) )
---> and the value is a string that is longer than '' (empty or blank) or the value is an array and this filter applied to it gives "true' or a positive result
&& ($key != 'main_page') && ($key != zen_session_name()) && ($key != 'error') && ($key != 'x') && ($key != 'y') ) {
---> and the key is not one of these names.
Apparently $value should not be an array if the key passes the "exclude" test. Casting it to int seems to make it safe, but destroys the test's value (unless it is a string starting with a number, it will be viewed as 0 (zero)); casting it to string will keep the information if it is a string, and hopefully make it safe if it is an array.
Best would be to find out why it is being an array when it apparently should not, and fixing that, or testing for it being an array and handling it appropriately if it is.


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